A) \[2.14\,\,V\]
B) \[1.80\,\,V\]
C) \[1.07\,\,V\]
D) \[0.82\,\,V\]
Correct Answer: C
Solution :
\[{{E}_{cell}}=E_{cell}^{o}-\frac{0.0591}{n}\log Q\] \[\underset{0.1\,\,M}{\mathop{C{{u}^{2+}}}}\,+Zn\xrightarrow{{}}\underset{1\,\,M}{\mathop{Z{{n}^{2+}}}}\,+Cu\] \[Q=\frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}=\frac{1}{0.1}=10\] \[{{E}_{cell}}=1.10-\frac{0.0591}{2}\log 10\] \[=1.10-0.295=1.0705\,\,V\]You need to login to perform this action.
You will be redirected in
3 sec