A) \[91\,\,nm\]
B) \[192\,\,nm\]
C) \[406\,\,nm\]
D) \[9.1\times {{10}^{-8}}nm\]
Correct Answer: A
Solution :
\[\frac{1}{\lambda }={{\bar{v}}_{H}}={{\bar{R}}_{H}}\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\] \[=1.097\times {{10}^{7}}\left[ \frac{1}{{{1}^{2}}}-\frac{1}{{{\infty }^{2}}} \right]\] \[\therefore \] \[\lambda =\frac{1}{1.097\times {{10}^{7}}}m\] \[=9.11\times {{10}^{-8}}m\] \[=91.1\times {{10}^{-9}}m\] \[=91.1\,\,nm\] \[(1\,\,nm={{10}^{-9}}m)\]
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