A) \[0.1%\]
B) \[1%\]
C) \[0.2%\]
D) \[0.8%\]
Correct Answer: C
Solution :
\[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \] \[{{T}^{2}}=4{{\pi }^{2}}\frac{l}{g}\] \[\Rightarrow \] \[g=\frac{4{{\pi }^{2}}l}{{{T}^{2}}}\] Here \[%\] error in \[l=\frac{1\,\,mm}{100\,\,cm}\times 100=\frac{0.1}{100}\times 100=0.1%\] and \[%\] error in\[T=\frac{0.1}{2\times 100}\times 100=0.05%\] \[\therefore \]\[%\]error in\[g=%\]error\[l+2(%\]\[\text{error}\,\,\text{in}\,\,T\text{)}\] \[=0.1+2\times 0.05\] \[=0.2%\]You need to login to perform this action.
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