A) \[{{30}^{o}}\]
B) \[{{45}^{o}}\]
C) \[{{60}^{o}}\]
D) \[{{0}^{o}}\]
Correct Answer: C
Solution :
Key Idea Slope of the path of the particle gives the measure of angle required. Draw the situation as shown.\[OA\]represents the path of the particle starting from origin\[O(0,\,\,0)\]. Draw a perpendicular from point\[A\]to\[x-\]axis. Let the path of the particle makes an angle\[\theta \]with the \[x-\]axis, then \[\tan \theta =\]slope of line\[OA\] \[=\frac{AB}{OB}=\frac{3}{\sqrt{3}}=\sqrt{3}\] or \[\theta ={{60}^{o}}\]You need to login to perform this action.
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