A) \[10\,\,m\Omega \] resistance is to be connected in parallel to the galvanometer
B) \[10\,\,m\Omega \] resistance is to be connected in series with the galvanometer
C) \[0.1\,\,\Omega \] resistance is to be connected in parallel to the galvanometer
D) \[0.1\,\,\Omega \] resistance is to be connected in series with the galvanometer
Correct Answer: A
Solution :
To convert a galvanometer into an ammeter, shunt resistance in parallel is connected galvanometer. Since, galvanometer \[G\] and shunt \[S\] are in parallel, hence\[{{i}_{g}}G=(i-{{i}_{g}})\] \[\Rightarrow \] \[S=\frac{{{i}_{g}}G}{i-{{i}_{g}}}\] \[=\frac{4\times {{10}^{-3}}\times 15}{6-4\times {{10}^{-3}}}\] \[=\frac{60\times {{10}^{-3}}}{5.996}\] \[=10\times {{10}^{-3}}\Omega \] \[=10\,\,m\Omega \]You need to login to perform this action.
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