A) \[y=3x+8\]
B) \[y=3x-8\]
C) \[y=3x+2\]
D) None of these
Correct Answer: D
Solution :
Let the equation of a line which is parallel to the line\[y-3x-4=0\]is \[y=3x+k\] Since, this is tangent to the hyperbola \[\frac{{{x}^{2}}}{3}-\frac{{{y}^{2}}}{2}=1\] \[\therefore \] \[k=\sqrt{3{{(3)}^{2}}-2}\] \[(\because \,\,k=\sqrt{{{a}^{2}}{{m}^{2}}-{{b}^{2}}})\] \[=\sqrt{25}=5\] \[\therefore \]Required line is\[y=3x+5\],You need to login to perform this action.
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