A) \[1\]
B) \[2\]
C) \[3\]
D) .\[6\]
Correct Answer: A
Solution :
In centre of triangle \[OAB\] is \[\left( \frac{0\times 5+3\times 4+0\times 3}{3+4+5},\,\,\frac{0\times 5+0\times 4+4\times 3}{3+4+5} \right)\] \[=(1,\,\,1)\] \[\therefore \]Equation of circle which touches both coordinates is \[{{(x-1)}^{2}}+{{(y-1)}^{2}}=1\] \[\Rightarrow \] \[{{x}^{2}}-2x+{{y}^{2}}-2y+1=0\] On comparing with \[{{x}^{2}}+{{y}^{2}}-2cx-2cy+{{c}^{2}}=0\], we get \[c=1\]You need to login to perform this action.
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