A) \[\frac{3}{25}\]
B) \[\frac{4}{35}\]
C) \[\frac{2}{35}\]
D) \[\frac{1}{35}\]
Correct Answer: C
Solution :
The total number of four digits number from the digits\[(1,\,\,2,\,\,3,\,\,4,\,\,5,\,\,6,\,\,7)\] \[=7\times 6\times 5\times 4\] The favourable four digits number whose sum of digits is less than. \[\therefore \]Total favourable four digits number \[=4!\,\,+4!\] \[=48\] \[\therefore \]Required probability\[=\frac{48}{7\times 6\times 5\times 4}\] \[=\frac{2}{35}\]You need to login to perform this action.
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