A) \[3\]
B) \[4\]
C) \[6\]
D) \[2\]
Correct Answer: A
Solution :
Number of a-particles\[=\frac{change\,\,in\,\,atomic\,\,mass}{4}\] \[=\frac{218-206}{4}=\frac{12}{4}=3\]You need to login to perform this action.
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