A) \[392\]
B) \[31.6\]
C) \[278\]
D) \[156\]
Correct Answer: A
Solution :
Mohr's salt is\[(N{{H}_{4}})S{{O}_{4}}\cdot FeS{{O}_{4}}\cdot 6{{H}_{2}}O\] The equation is: \[5F{{e}^{2+}}+MnO_{4}^{-}+8{{H}^{+}}\xrightarrow{{}}\] \[5F{{e}^{3+}}+M{{n}^{2+}}+4{{H}_{2}}O\] Total change in oxidation number of iron \[=(+3)+(-2)\] \[=+1\] So, equivalent wt. of Mohr's salt \[=\frac{Mol.\,\,wt.\,\,Mohr's\,\,salt}{1}\] \[=\frac{392}{1}\] \[=392\]
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