A) \[600\,\,Hz\]
B) \[585\,\,Hz\]
C) \[645\,\,Hz\]
D) \[666\,\,hz\]
Correct Answer: D
Solution :
The perceived frequency \[(f')\] is related to the actual frequency \[({{f}_{0}})\] and the relative speeds of the source \[({{v}_{s}})\] and observer \[({{v}_{0}})\] and the speed \[(v)\] of waves in the medium is given by \[f'={{f}_{o}}\left( \frac{v+{{v}_{o}}}{v-{{v}_{s}}} \right)\] Given,\[v=340\,\,m/s,\,\,{{v}_{o}}=15\,\,m/s,\,\,{{v}_{s}}=20\,\,m/s\] \[\therefore \] \[f'=600\times \left( \frac{340+15}{340-20} \right)\] \[=\frac{355}{320}\times 600=666\,\,Hz\]You need to login to perform this action.
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