A) \[8%\]
B) \[9%\]
C) \[10%\]
D) \[91%\]
Correct Answer: C
Solution :
Let \[G\] be resistance of galvanometer and \[{{i}_{g}}\] the current which on passing through the galvanometer produces full scale deflection. If \[i\] is the maximum current, and since, \[G\]and \[S\] are in parallel. \[{{i}_{g}}\times G=(i-{{i}_{g}})\times S\] \[\Rightarrow \] \[\frac{{{i}_{g}}}{i}=\frac{S}{S+G}\] Given, \[G=36\Omega ,\,\,S=4\Omega \] \[\therefore \] \[\frac{{{i}_{g}}}{i}=\frac{4}{36+4}=\frac{4}{40}\] \[\Rightarrow \] \[{{i}_{g}}=\frac{i}{10}\] \[\therefore \] \[100\times \frac{{{i}_{g}}}{i}=\frac{1}{10}\times 100\] \[\Rightarrow \] \[\frac{{{i}_{g}}}{i}%=10%\]You need to login to perform this action.
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