A) \[-16\]
B) \[-8\]
C) \[-24\]
D) \[24\]
Correct Answer: D
Solution :
We know that, the equation of normal to the parabola \[{{y}^{2}}=4ax\]is \[y=mx-2am-a{{m}^{3}}\] Equation of normal to the parabola \[{{y}^{2}}=-8x\] is \[y=mx+4m+2{{m}^{3}}\] ? (i) \[(\because \,\,a=2)\] But given normal is \[2x+y+k=0\] ... (ii) Comparing Eqs. (i) and (ii), we get \[m=-2\]and\[k=-4m-2{{m}^{3}}\] \[\Rightarrow \] \[k=8+16\] \[\Rightarrow \] \[k=24\]You need to login to perform this action.
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