A) \[212\,\,kPa\]
B) \[209\,\,kPa\]
C) \[206\,\,kPa\]
D) \[200\,\,kPa\]
Correct Answer: B
Solution :
The ideal gas law is the equation of state of an ideal gas. The state of an amount of gas is determined , by/'its . pressure, volume and temperature . The equation has the form \[pV=nRT\] where, \[p\] is pressure, \[V\] the volume, \[n\] the number of moles, R the gas constant and T the temperature. \[\therefore \] \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}{{V}_{2}}}{{{T}_{2}}}\] Given\[,\] \[{{p}_{1}}=200\,\,kPa,\,\,{{V}_{1}}=V\], \[{{T}_{1}}=273+22=295\,\,K\], \[{{V}_{2}}=V+0.02\,\,V,\,\,{{T}_{2}}=273+42=315\,\,K\] \[\frac{200\times V}{295}=\frac{{{p}_{2}}\times 1.02\,\,V}{315}\] \[\Rightarrow \] \[{{P}_{2}}=\frac{200\times 315}{295\times 1.02}\] \[{{P}_{2}}\approx 209\,\,kPa\]
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