A) \[1150\,\,N\]
B) \[1250\,\,N\]
C) \[1300\,\,N\]
D) \[1420\,\,N\]
Correct Answer: B
Solution :
Friction between block \[A\] and block \[B\] and between block \[B\] and surface will oppose the\[P\]. \[\therefore \] \[P={{F}_{AB}}+{{F}_{BS}}\] \[={{\mu }_{AB}}{{m}_{A}}g+{{\mu }_{BS}}({{m}_{A}}+{{m}_{B}})g\] \[=0.25\times 100\times 10+\frac{1}{3}(100+200)\times 10\] \[=1250\,\,N\]You need to login to perform this action.
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