A) \[{{f}_{o}}=45\,\,cm\]and\[{{f}_{e}}=-9\,\,cm\]
B) \[{{f}_{o}}=-7.2\,\,cm\]and\[{{f}_{e}}=5\,\,cm\]
C) \[{{f}_{o}}=50\,\,cm\]and\[{{f}_{e}}=10\,\,cm\]
D) \[{{f}_{o}}=30\,\,cm\]and\[{{f}_{e}}=6\,\,cm\]
Correct Answer: D
Solution :
In this case \[|m|=\frac{{{f}_{o}}}{{{f}_{e}}}=5\] ... (i) and length of telescope \[{{f}_{o}}+{{f}_{e}}=36\] ... (ii) Solving Eqs. (i) and (ii), we get \[{{f}_{e}}=6\,\,cm,\,\,{{f}_{o}}=30\,\,cm\]You need to login to perform this action.
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