A) 2-ethylprop-2-en-1-ol
B) 2-hydroxymethylbutan-1-ol
C) 2-methylenebutan-1-pl
D) 2-ethyl-3-hydroxyprop-1-ene
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}-\underset{\begin{smallmatrix} _{3}|| \\ C{{H}_{2}} \end{smallmatrix}}{\mathop{\overset{2}{\mathop{C}}\,}}\,-\overset{1}{\mathop{C}}\,{{H}_{2}}OH\] 2-ethylprop-2-en-1-olYou need to login to perform this action.
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