A) carbon dioxide
B) chlorine
C) iodine
D) sulphur dioxide
Correct Answer: B
Solution :
\[C{{l}_{2}}\] being a stronger oxidising agent oxidises bromide present in the mother liquor to\[B{{r}_{2}}\]. \[\underset{from\,\,mother\,\,liquor}{\mathop{2B{{r}^{-}}}}\,+C{{l}_{2}}\xrightarrow{{}}\underset{bromide}{\mathop{B{{r}_{2}}}}\,+2C{{l}^{-}}\]You need to login to perform this action.
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