A) \[\log \sin x\]
B) \[\cot x\]
C) \[\sin x\]
D) \[\log \cos x\]
Correct Answer: B
Solution :
We have the differential equation \[\frac{dy}{dx}+Py=Q\] Integrating factor of this differential equation \[=\sin x\] \[\Rightarrow \] \[{{e}^{\int{Pdx}}}=\sin x\] \[\Rightarrow \] \[\int{Pdx}=\log \sin x\] \[\Rightarrow \] \[P=\frac{d}{dx}(\log \sin x)\] \[\Rightarrow \] \[P=\frac{1}{\sin x}\cdot \cos x\] \[\Rightarrow \] \[P=\cot x\]You need to login to perform this action.
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