JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    In the figure, charge and the potential difference across the 4uF capacitor will be nearly

    A) \[600\mu C,\,\,150\,\,V\]            

    B) \[300\,\,\mu C,\,\,75\,\,V\]

    C)  \[800\,\,\mu C,\,\,200\,\,V\]    

    D)  \[580\,\,\mu C,\,\,145\,\,V\]

    Correct Answer: D

    Solution :

    \[\frac{1}{C}=\frac{1}{20}+\frac{1}{8}+\frac{1}{12}\]                 \[\frac{1}{C}=\frac{6+15+10}{120}\] or            \[C=\frac{120}{31}\mu F\] Now,     \[Q=CV=\frac{120}{31}\times 300\,\,\mu C\] charge across\[4\mu F\]                 \[=\frac{120\times 300}{31\times 2}=580.6\,\,\mu C\] Voltage across\[4\mu F\]                 \[=\frac{580.6}{4}V=145.15\,\,V\]


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