2. Solved Papers
  3. JCECE Engineering

JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    The line \[\frac{x-2}{3}=\frac{y+1}{2}=\frac{z-1}{-1}\] intersects the curve\[xy=c,\,\,z=0\], if \[c\] equals to

    A) \[\pm 1\]                                            

    B) b)\[\pm \frac{1}{3}\]

    C) \[\pm \sqrt{5}\]                                              

    D)  None of these

    Correct Answer: C

    Solution :

    The point on the line where it intersects the curve, we have\[z=0\]. So that,                 \[\frac{x-2}{3}=\frac{y+1}{2}=\frac{0-1}{-1}\] \[\Rightarrow \]               \[\frac{x-2}{3}=1\]and\[\frac{y+1}{2}=1\] \[\Rightarrow \]               \[x=5\]and\[y=1\] Putting these values of \[x\] and \[y\] in\[xy={{c}^{2}}\], we get                 \[{{c}^{2}}=5\] \[\Rightarrow \]               \[c=\pm \sqrt{5}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner