2. Solved Papers
  3. JCECE Engineering

JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    If\[f'(2)=2\],\[f''(2)=1\], then\[\underset{x\to 2}{\mathop{\lim }}\,\frac{2{{x}^{2}}-4f'(x)}{x-2}\] is

    A) \[4\]                                     

    B) \[0\]

    C) \[2\]                                     

    D) \[\infty \]

    Correct Answer: A

    Solution :

    \[\underset{x\to 2}{\mathop{\lim }}\,\frac{2{{x}^{2}}-4f'(x)}{x-2}=\underset{x\to 2}{\mathop{\lim }}\,\frac{4x-4f''(x)}{1}\]                 \[=8-4f'(2)=8-4=4\]


You need to login to perform this action.
You will be redirected in 3 sec spinner