A) \[K=e\]
B) \[l=m\]
C) \[K=\frac{1}{e}\]
D) None of these
Correct Answer: B
Solution :
\[{{I}_{m}}=\int_{1}^{x}{{{({{\log }_{x}})}^{m}}}dx=[{{(\log x)}^{m}}\cdot x]_{1}^{x}\] \[-\int_{1}^{x}{m{{(\log x)}^{m}}^{-1}\cdot \frac{1}{x}}\cdot x\,\,dx\] \[={{(\log x)}^{m}}\cdot x-m\cdot {{I}_{m-1}}\]You need to login to perform this action.
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