A) \[150\,\,kcal\]
B) \[200\,\,kcal\]
C) \[250\,\,kcal\]
D) \[350\,\,kcal\]
Correct Answer: B
Solution :
When \[2.0\,\,g\] or\[\left( or\,\,\frac{2}{16}\,\,mol \right)\]methane is burnt, heat evolved\[=25\,\,kcal\]. \[\therefore \]When \[1\,\,mol\] methane is burnt, heat evolved will be \[=\frac{25}{(2/16)}=\frac{25\times 16}{2}=200\,\,kcal\]You need to login to perform this action.
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