A) \[HCl{{O}_{3}}\]and\[C{{l}_{2}}O\]
B) \[HCl{{O}_{2}}\]and\[HCl{{O}_{4}}\]
C) \[HCl\]and\[C{{l}_{2}}O\]
D) \[HCl\]and\[HCl{{O}_{3}}\]
Correct Answer: D
Solution :
In disproportionation reactions, the same element is oxidised as well as reduced. In\[HOCl\], the oxidation state of\[Cl\]is\[+1\]. In\[HCl{{O}_{3}},\,\,C{{l}_{2}}O,\,\,HCl{{O}_{2}},\,\,HCl{{O}_{4}}\]and\[HCl\], the oxidation states of \[Cl\] are\[+5,\,\,+1,\,\,+3,\,\,+7\]and\[-1\]respectively. Thus, the disproportionation products are \[HCl\] and\[HCl{{O}_{3}}\].You need to login to perform this action.
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