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JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    The path difference between two wave fronts emitted by coherent sources of wavelength \[5460\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\] is \[2.1\] micron. The phase difference between the wave fronts at that point is

    A) \[7.692\,\,rad\]                

    B) \[7.692\,\,\pi \,\,rad\]

    C)  \[\frac{7.692}{\pi }rad\]                              

    D)  \[\frac{7.692}{3\pi }rad\]

    Correct Answer: B

    Solution :

    Phase difference\[\phi =\frac{2\pi }{\lambda }x\]                 \[=\frac{2\pi \times 2.1\times {{10}^{-6}}}{5460\times {{10}^{-10}}}\]                 \[=7.692\,\,\pi \,\,rad\]


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