A) \[1:\cos \theta \]
B) \[\cos \theta :1\]
C) \[1:\sin \theta \]
D) \[\sin \theta :1\]
Correct Answer: A
Solution :
Here,\[\tan \delta =\frac{V}{H}\]and\[\tan \delta '=\frac{V}{H\cos \theta }\] \[\therefore \] \[\frac{\tan \delta '}{\tan \delta }=\frac{V}{H\cos \theta }\times \frac{H}{V}\] \[=\frac{1}{\cos \theta }\]You need to login to perform this action.
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