A) \[0.1\,\,M\]
B) \[0.001\,\,M\]
C) \[0.01\,\,M\]
D) \[{{10}^{-4}}M\]
Correct Answer: B
Solution :
Molarity of \[N{{a}_{2}}C{{O}_{3}}\] solution \[=\frac{2.65}{106}\times \frac{1}{250}\times 1000=0.1\,\,M\] \[{{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\] \[10\times 0.1=1000\times {{M}_{2}}\] \[\therefore \] \[{{M}_{2}}=\frac{10\times 0.1}{1000}=0.001\,\,M\]You need to login to perform this action.
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