A) \[36\,\,kW\]
B) \[18\,\,kW\]
C) \[45\,\,kW\]
D) \[54\,\,kW\]
Correct Answer: C
Solution :
Power required for rotar,\[P=\tau \cdot W\] \[=36\,\,kW\] Power of engine\[{{P}_{0}}=\frac{P}{0.8}=45\,\,kW\]You need to login to perform this action.
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