A) adding \[Mg\] powder
B) boiling the acid
C) passing \[N{{H}_{3}}\] through acid
D) passing air through warm acid
Correct Answer: D
Solution :
Brown colour of \[HN{{O}_{3}}\] is due to the presence of\[N{{O}_{2}}\], which is formed by its decomposition. \[4HN{{O}_{3}}\xrightarrow{Sunlight}\underset{brown}{\mathop{4N{{O}_{2}}}}\,+2{{H}_{2}}O+{{O}_{2}}\] When air is passed, the equilibrium shifts towards left hand side and brown colour is removed.
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