A) \[M\times l\]
B) \[\frac{M}{l}\]
C) \[\frac{2M}{\pi }\]
D) \[M\]
Correct Answer: C
Solution :
When wire is bent in the form of semi circular arc then,\[l=\pi r\] \[\therefore \]The radius of semi-circular arc\[,\]\[r=l/\pi \]. Distance between two end points of semi-circular wire\[=2\pi =\frac{2l}{\pi }\] \[\therefore \]Magnetic moment of semi-circular wire \[=m\times 2\pi \] \[=m\times \frac{2l}{\pi }=\frac{2}{\pi }ml\] But \[ml\] is the magnetic moment of straight wire \[i.e.,\] \[ml=M\] \[\therefore \]New magnetic moment\[=\frac{2}{\pi }M\]You need to login to perform this action.
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