A) \[2\]
B) \[4\]
C) \[5\]
D) None of these
Correct Answer: A
Solution :
Maximum energy, is liberated for, transition \[{{E}_{n}}\to 1\] and minimum energy for\[{{E}_{n}}\to {{E}_{n-1}}\] Hence\[,\]\[\frac{{{E}_{1}}}{{{n}^{2}}}-{{E}_{1}}=52.224\,\,eV\] ... (i) and \[\frac{{{E}_{1}}}{{{n}^{2}}}=\frac{{{E}_{1}}}{{{(n-1)}^{2}}}=1.224\,\,eV\] ... (ii) Solving Eqs. (i) and (ii), we get \[{{E}_{1}}=-54.4\,\,eV\] and \[n=5\] But \[{{E}_{1}}=\frac{13.6{{Z}^{2}}}{{{1}^{2}}}\] \[\Rightarrow \] \[Z=2\]You need to login to perform this action.
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