A) \[\cos x\]
B) \[\frac{1}{\cos x}\]
C) \[\frac{1}{\sin x}\]
D) \[\frac{1}{\tan x}\]
Correct Answer: B
Solution :
In first case, \[\tan \theta =\frac{{{B}_{V}}}{{{B}_{H}}}\] ... (i) In second case, \[\tan \theta '=\frac{{{B}_{V}}}{{{B}_{H}}\cos x}\] ... (ii) From Eqs. (i) and (ii), we get \[\frac{\tan \theta '}{\tan \theta }=\frac{1}{\cos x}\]You need to login to perform this action.
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