A) resistance\[R=46\Omega \]
B) current through \[20\Omega \] resistance is\[0.1\,\,A\]
C) potential difference across the middle resistance is\[2V\]
D) All of the above are true
Correct Answer: D
Solution :
\[\frac{1}{R'}=\frac{1}{10}+\frac{1}{10}+\frac{1}{20}\] \[\Rightarrow \] \[R'=\frac{20}{5}=4\Omega \] Now, using Ohm's law,\[i=\frac{25}{R+R'}\] \[\Rightarrow \] \[0.5=\frac{25}{R+4}\] \[\Rightarrow \] \[R+4=\frac{25}{0.5}\] \[\Rightarrow \] \[R=50-4=46\Omega \] Current through \[20\Omega \] resistor \[=\frac{0.5\times 5}{20+5}=\frac{2.5}{25}=0.1\,\,A\] Potential-difference across middle resistor = Potential difference across\[20\Omega \] \[=20\times 0.1=2\,\,V\]You need to login to perform this action.
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