A) \[{{K}_{2}}=\frac{1}{{{K}_{1}}}\]
B) \[{{K}_{2}}=K_{1}^{2}\]
C) \[{{K}_{2}}=\frac{{{K}_{1}}}{2}\]
D) \[{{K}_{2}}=\frac{1}{K_{1}^{2}}\]
Correct Answer: D
Solution :
(i)\[NO(g)N{{O}_{2}}(g)\] So\[,\] \[{{K}_{1}}=\frac{[N{{O}_{2}}]}{[NO]{{[{{O}_{2}}]}^{1/2}}}\] ? (i) (ii)\[2N{{O}_{2}}(g)2NO+{{O}_{2}}(g)\] So\[,\] \[{{K}_{2}}=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}\] ? (ii) From Eq. (i) \[K_{1}^{2}=\frac{{{[N{{O}_{2}}]}^{2}}}{{{[NO]}^{2}}[{{O}_{2}}]}\] or \[\frac{1}{K_{1}^{2}}=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}\] ? (iii) From Eqs. (ii) and (iii) \[{{K}_{2}}=\frac{1}{K_{1}^{2}}\]You need to login to perform this action.
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