A) \[0\]
B) \[1\]
C) \[-1\]
D) \[\frac{1}{2}\]
Correct Answer: B
Solution :
Given, planes are \[x-cy-bz=0\] ... (i) \[ex-y+az=0\] ... (ii) \[bx+ay-z=0\] ... (iii) Equation of plane passing through the line of intersection of planes (i) and (ii) may be taken as \[(x-cy-bz)+\lambda (cx-y+az)=0\] \[(1+c\lambda )x+y(-c-\lambda )+z(-b+a\lambda )=0\] ... (iv) Now, planes (iii) and (iv) are same. \[\therefore \] \[\frac{1+c\lambda }{b}=\frac{-(c+\lambda )}{a}=\frac{-b+a\lambda }{-1}\] By eliminating\[\lambda \], we get \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}+2abc=1\]You need to login to perform this action.
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