A) an even function
B) an odd function
C) neither even nor odd
D) a periodic function
Correct Answer: B
Solution :
We have, \[uov(-x)\] \[=u[v(-x)]\] \[=u[-v(x)]\] [\[\because v\]is odd] \[=-u[v(x)]\] [\[\because \,\,u\]is odd] \[=-uov(x)\] Thus, \[uov\] is an odd function.You need to login to perform this action.
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