A) a circle
B) a parabola
C) an ellipse
D) a hyperbola
Correct Answer: A
Solution :
Let\[z=x+iy\] Then, \[\bar{z}=x-iy\] Given, equation is\[z\bar{z}+z+\bar{z}+10=0\] \[\Rightarrow \]\[(x+iy)+(x-iy)+(x+iy)+(x-iy)+10=0\] \[\Rightarrow \]\[{{x}^{2}}+{{y}^{2}}+2x+10=0\] It represents the equation of a circle.You need to login to perform this action.
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