A) \[0\]
B) \[1\]
C) \[2\]
D) infinite
Correct Answer: A
Solution :
Given,\[\sin 2x+\cos 4x=2\] \[\Rightarrow \] \[\sin 2x=1\], \[\cos 4x=1\] \[\Rightarrow \] \[1-2{{\sin }^{2}}2x=1\] \[\Rightarrow \] \[1-2=1\]which is not possible. Thus, there is no solution of the given equation.You need to login to perform this action.
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