A) \[-3\]
B) \[3\]
C) \[1\]
D) \[-1\]
Correct Answer: B
Solution :
Given, equation is \[xy-\log y=1\] On differentiating it w.r.t\[.x,\] we get \[xy'+y\cdot 1-\frac{1}{y}\cdot y'=0\] \[\Rightarrow \] \[xyy'+{{y}^{2}}-y'=0\] Again, differentiating w.r.t. x, we get \[(xy-1)y''+y'(xy'+y\cdot 1)+2yy'=0\] \[\Rightarrow \] \[x(yy''+y{{'}^{2}})-y''+3yy'=0\] Comparing it with the given equation, we get \[k=3\]You need to login to perform this action.
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