A) \[1:3\]electrolyte
B) \[1:2\]electrolyte
C) \[1:1\]electrolyte
D) \[3:1\]electrolyte
Correct Answer: B
Solution :
Formation of \[0.2\] mole of \[AgCl\] from \[0.1\] mole of complex means that there are two ionisable\[Cl\]. Hence, formula is \[[Co{{(N{{H}_{3}})}_{5}}Cl]C{{l}_{2}}]\,\,i.e.,\,\,1:2\] type electrolyte.You need to login to perform this action.
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