A) \[\frac{1}{2}<\alpha <\frac{1}{\sqrt{2}}\]
B) \[\frac{1}{2}<\alpha <\frac{1}{3}\]
C) \[\frac{1}{3}<\alpha <\frac{1}{\sqrt{3}}\]
D) \[\frac{1}{4}<\alpha <\frac{1}{2}\]
Correct Answer: C
Solution :
The point should lies on the opposite side of the origin of the line\[~x+y-1=0\]You need to login to perform this action.
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