A) \[9\times {{10}^{13}}J\]
B) \[9\times {{10}^{16}}J\]
C) \[9\times {{10}^{17}}J\]
D) \[9\times {{10}^{19}}J\]
Correct Answer: A
Solution :
\[E=(\Delta m){{c}^{2}}=\left( \frac{0.1}{100}\times 1 \right){{(3\times {{10}^{8}})}^{2}}\] \[=9\times {{10}^{13}}J\]
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