A) \[\frac{Ma}{(g+a)}\]
B) \[\frac{2Ma}{(g+a)}\]
C) \[\frac{M}{(g+a)}\]
D) Not Possible
Correct Answer: B
Solution :
Let the retarding force acting on the balloon in vertically upward direction be\[F\]. When the balloon is descending down with acceleration a, its equation of motion can be given as \[Ma=Mg-F\] or \[F=Mg-Ma\] ? (i) Let \[M\] mass is removed from the balloon. When it moves up with acceleration\[a\], its equation of motion can be given as \[(M-m)a=F-(M-m)g\] From Eq. (i) \[Ma-ma=Mg-Ma-Mg+mg\] \[\Rightarrow \] \[m=\frac{2Ma}{(g+a)}\]You need to login to perform this action.
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