A) \[S<Se<Cl\]
B) \[Se<S<Cl\]
C) \[Cl<S<Se\]
D) \[Se=S<Cl\]
Correct Answer: B
Solution :
lonisation energy generally increase from left to right across a row of the Periodic Table and decreases from top to bottom down a group. Hence, \[IE\] of \[CI>S\] and \[IE\] of\[Se<S\]. Thus, the order is\[Se<S<Cl\].You need to login to perform this action.
You will be redirected in
3 sec