A) \[6\,\,mm\]
B) \[9\,\,mm\]
C) \[12\,\,mm\]
D) \[18\,\,mm\]
Correct Answer: C
Solution :
We have, \[I={{I}_{0}}{{e}^{-\mu x}}\] \[\therefore \] \[\frac{1}{8}={{e}^{-4.36}}\] \[\Rightarrow \] \[{{\left( \frac{1}{2} \right)}^{3}}={{e}^{-4.36}}={{({{e}^{-\mu x}})}^{3}}\] or \[-3\mu x=-36\mu \] \[\Rightarrow \] \[x=12\,\,mm\]You need to login to perform this action.
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