A) \[2{{\cos }^{-1}}\frac{\mu }{2}\]
B) \[2{{\sin }^{-1}}\frac{\mu }{2}\]
C) \[2{{\cos }^{-1}}\mu \]
D) \[2{{\sin }^{-1}}\mu \]
Correct Answer: A
Solution :
According to Snell's law \[\mu =\frac{\sin i}{\sin r}\] \[i=2r\] \[\mu =\frac{\sin 2r}{\sin r}\Rightarrow \mu =\frac{2\sin r\cos r}{\sin r}\] \[{{\cos }^{-1}}\frac{\mu }{2}=r\] \[\]
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