A) \[24\,\,m\]
B) \[40\,\,m\]
C) \[56\,\,m\]
D) \[16\,\,m\]
Correct Answer: C
Solution :
Distance travelled by the particle is \[x=40+12t-{{t}^{3}}\] \[v=\frac{dx}{dt}=2-3{{t}^{2}}\] But final velocity\[v=0\] \[12-3{{t}^{2}}=0\] \[{{t}^{2}}=\frac{12}{3}=4\] \[t=2s\] \[x=40+12(2)-8=56\,\,m\]You need to login to perform this action.
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