A) \[1.5\times {{10}^{-5}}N-m\]
B) \[1.5\times {{10}^{-3}}N-m\]
C) \[1.5\times {{10}^{-2}}N-m\]
D) \[1.5\times {{10}^{-6}}N-m\]
Correct Answer: A
Solution :
\[C=MB\sin \theta \] \[=(m\times 2l)\times 2\times {{10}^{-5}}\sin {{30}^{o}}\] \[=150\times {{10}^{-2}}\times 2\times {{10}^{-5}}\times \frac{1}{2}=1.5\times {{10}^{-5}}N-m\]You need to login to perform this action.
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