A) \[321\,\,Hz\]
B) \[296\,\,Hz\]
C) \[289\,\,Hz\]
D) \[280\,\,Hz\]
Correct Answer: A
Solution :
The component of velocity of source along line joining \[{{v}_{s}}={{v}_{1}}\cos {{45}^{o}}=36\times \frac{1}{\sqrt{2}}\] Component of velocity of observer along line joining \[{{v}_{0}}={{v}_{2}}\cos {{45}^{o}}\] \[=72\times \frac{1}{\sqrt{2}}\] \[=10\sqrt{2}\] The frequency of horn \[n'=\frac{v+{{v}_{0}}}{v-{{v}_{s}}}\] \[n=\frac{330+10\sqrt{2}}{330-5\sqrt{2}}\times 280\] \[=\frac{344}{323}\times 280=298\,\,Hz\]You need to login to perform this action.
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